Practicing Success
In a parallel plate capacitor of capacitance C, a metal sheet is inserted between the plates, parallel to them. The thickness of the sheet is half of the separation between the plates. The capacitance now becomes |
4C 2C C/2 C/4 |
2C |
Before the metal sheet is inserted, $C=\varepsilon_0 A / d$ After the sheet is inserted, the system is equivalent to two capacitors in series, each of capacitance C' = $\frac{\varepsilon_0 A}{d / 4}$ = 4C The equivalent capacity is now 2C. ∴ (B) |