Three of the following four letter groups are alike in a certain way and one is different. Choose the odd one out.
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → JLJL
Write each letter’s place in the alphabet (A = 1, B = 2, …, Z = 26) and find the jumps from one letter to the next.
Option (1) JLJL — J (10), L (12), J (10), L (12): jumps +2, −2, +2.
Option (2) EGFH — E (5), G (7), F (6), H (8): jumps +2, −1, +2.
Option (3) IKJL — I (9), K (11), J (10), L (12): jumps +2, −1, +2.
Option (4) CEDF — C (3), E (5), D (4), F (6): jumps +2, −1, +2.
Three groups go +2, −1, +2; JLJL goes +2, −2, +2, so JLJL is the odd one out.