If in a right angled ΔPQR , tanQ = 5/12, then what is the value of co…

We are given that :-

tanQ = \(\frac{5}{12}\)

{ we know , tanQ = \(\frac{P}{B}\) }

By using pythagoras theorem,

P² + B² = H²

5² + 12² = H²

H = 13

Now,

cosQ

= \(\frac{B}{H}\) 

= \(\frac{12}{13}\)