If in a right angled ΔPQR , tanQ = 5/12, then what is the value of cos Q?

12/5 13/5 12/13 5/13

12/13

We are given that :- tanQ = \(\frac{5}{12}\) { we know , tanQ = \(\frac{P}{B}\) } By using pythagoras theorem, P² + B² = H² 5² + 12² = H² H = 13 Now, cosQ = \(\frac{B}{H}\)  = \(\frac{12}{13}\)