The area of the region bounded by the curve y = x 2 and the line y = 16
Answer & explanation
Correct answer: option 2
\(⇒2\int_{0}^{16}\sqrt{y}dy\)
$=2. \frac{2}{3}\begin{bmatrix}y^{\frac{3}{2}}\end{bmatrix}_0^{16}$
$⇒2(\frac{2}{3})[4^3]$
$=\frac{256}{3}$ sq. units