Gold is 19 times as heavy as water and copper is 9 times as heavy as water. In what ratio should these be mixed to get an alloy which is 15 times heavy as water?
Answer & explanation
Correct answer: option 4
Considering, Gold - G, Water - W & Copper - C
\(\frac{G}{W}\) = \(\frac{19}{1}\)
\(\frac{C}{W}\) = \(\frac{9}{1}\)
G : C : W
19 : 9 : 1
Water is constant
Use allegation:
