The velocity of freely falling body changes as $g^ph^q$ , where g is acceleration due to gravity and h is the height. The value of p and q are
Answer & explanation
Correct answer: option 2
Dimension of velocity v = dimension of $g^ph^q$
$M^0LT^{-1}$=$[MLT^{-2}]^p[M^0LT^0]^q$ = $M^0L^{p+q}T^{-2p}$
Comparing exponent from both sides
p+q = 1
-2p = -1 ⇒p= $\frac{1}{2}$
⇒q= $\frac{1}{2}$