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If $\frac{(17)^3+(7)^3}{\left(17^2+7^2-k\right)}=24$, then what is the value of k ? |
119 128 24 109 |
119 |
a3 + b3 = ( a + b ) ( a2 + b2 - ab ) ( a + b ) = \(\frac{a^3 + b^3}{a^2 + b^2 - ab }\) If $\frac{(17)^3+(7)^3}{\left(17^2+7^2-k\right)}=24$ By comparing the values from both of the equation we get = a = 17 b = 9 ab = 17 × 9 = 119 |
