If $\frac{(17)^3+(7)^3}{\left(17^2+7^2-k\right)}=24$, then what is the value of k ?
Answer & explanation
Correct answer: option 1
a3 + b3 = ( a + b ) ( a2 + b2 - ab )
( a + b ) = \(\frac{a^3 + b^3}{a^2 + b^2 - ab }\)
If $\frac{(17)^3+(7)^3}{\left(17^2+7^2-k\right)}=24$
By comparing the values from both of the equation we get =
a = 17
b = 9
ab = 17 × 9 = 119