Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

Options:

a

b

c

d

Correct Answer:

d

Explanation:

$ tan\phi = \frac{X_L}{R} = 1 $

$\Rightarrow R = X_L $

$ Z = 100\Omega = \sqrt {R^2 + X_L^2}=  X_L \sqrt 2$

$ X_L = \frac{100}{\sqrt 2} = 70.7 \Omega $

$ 2\pi fL = 70.7 \Omega $

$\Rightarrow L = \frac{70.7}{2000\pi} = 1.1 \times 10^{-2} henry$