The direction cosines of the line $x-y+z-5=0=x-3 y-6=0$ are:

$2,-4,1$ $3,1,-2$ $\frac{3}{\sqrt{14}}, \frac{1}{\sqrt{14}}, \frac{-2}{\sqrt{14}}$ $\frac{2}{\sqrt{14}}, \frac{-4}{\sqrt{14}}, \frac{1}{\sqrt{14}}$

$\frac{3}{\sqrt{14}}, \frac{1}{\sqrt{14}}, \frac{-2}{\sqrt{14}}$

The correct answer is Option (3) → $\frac{3}{\sqrt{14}}, \frac{1}{\sqrt{14}}, \frac{-2}{\sqrt{14}}$