The domain of real valued function $f(x)=\sqrt{e^{\cos^{-1}(\log_4x^2)}}$ is
Answer & explanation
Correct answer: option 2
For $D_f:|\log_4x^2|≤1$
$⇒-1≤\log_4x^2≤1⇒\frac{1}{4}≤x^2≤4⇒\frac{1}{2}≤x≤2$ or $-2≤x≤-\frac{1}{2}$
Hence $D_f=\left[-2,-\frac{1}{2}\right]∪\left[\frac{1}{2},2\right]$