Practicing Success
If cosθ + secθ = \(\frac{3}{√2}\) and 0 < θ ≤ 90° . Find the value of θ . |
90° 15° 30° 45° |
45° |
cosθ + secθ = \(\frac{3}{√2}\) Put θ = 45° ⇒ cos45° + sec45° = \(\frac{1}{√2}\) + √2 = \(\frac{3}{√2}\) satisfied the equation , so θ = 45° |