If cosθ + secθ =&n

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Target Exam

CUET

Subject

General Aptitude Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

If cosθ + secθ = \(\frac{3}{√2}\) and 0 < θ ≤ 90° . Find the value of θ .

Options:

90°

15°

30°

45°

Correct Answer:

45°

Explanation:

cosθ + secθ = \(\frac{3}{√2}\)

Put θ = 45°

⇒ cos45° + sec45° = \(\frac{1}{√2}\) + √2 = \(\frac{3}{√2}\)

satisfied the equation ,

so θ = 45°