Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Waves

Question:

A capacitor having a capacity of 2 pF. Electric field across the capacitor is changing with a value of 1012 Vs−1 . The displacement current is

Options:

2 A

4 A

6 A

10 A

Correct Answer:

2 A

Explanation:

$i =\frac{dQ}{dt}=\frac{d}{dt}(CV)$

$ = C\frac{dV}{dt}= 2 × 10^{-12} × 10^{12} = 2 \, A$