A capacitor having a capacity of 2 pF. Electric field across the capacitor is changing with a value of 1012 Vs−1 . The displacement current is
Answer & explanation
Correct answer: option 1
$i =\frac{dQ}{dt}=\frac{d}{dt}(CV)$
$ = C\frac{dV}{dt}= 2 × 10^{-12} × 10^{12} = 2 \, A$