At a place, vertical component of earth's magnetic field is $\sqrt{3}$ times its horizontal component. If total intensity of earth's magnetic field at the place is 0.4G, then the horizontal component of carth's magnetic field?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 0.2 G
$B_H$ = Horizontal component of Earth's Magnetic field = 0.4 G
$B_V$ = Vertical component of Earth's Magnetic field = $\sqrt{3}B_H$
$B_T=\sqrt{B_H^2+B_V^2}$
$=\sqrt{B_H^2+(\sqrt{3}B_H)^2}$
$=2B_H$
$∴2B_H=0.4G$
$B_H=0.2G