Match List-I with List-II.
|
List-I Ions |
List-II No. of unpaired electrons |
|
(A) $Zn^{2+}$ |
(I) 0 |
|
(B) $Cu^{2+}$ |
(II) 4 |
|
(C) $Ni^{2+}$ |
(III) 1 |
|
(D) $Fe^{2+}$ |
(IV) 2 |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → (A) - (I), (B) - (III), (C) - (IV), (D) - (II)
Match List-I with List-II.
|
List-I Ions |
List-II No. of unpaired electrons |
|
(A) $Zn^{2+}$ |
(I) 0 |
|
(B) $Cu^{2+}$ |
(III) 1 |
|
(C) $Ni^{2+}$ |
(IV) 2 |
|
(D) $Fe^{2+}$ |
(II) 4 |
Number of unpaired electrons depends on electronic configuration of ions.
(A) Zn²⁺
Zn = [Ar] 3d¹⁰ 4s²
Zn²⁺ → remove 2 electrons from 4s
Zn²⁺ = [Ar] 3d¹⁰
All electrons paired → 0 unpaired
Matches (I)
(B) Cu²⁺
Cu = [Ar] 3d¹⁰ 4s¹
Cu²⁺ → remove 1 from 4s and 1 from 3d
Cu²⁺ = [Ar] 3d⁹
d⁹ → 1 unpaired electron
Matches (III)
(C) Ni²⁺
Ni = [Ar] 3d⁸ 4s²
Ni²⁺ → remove 2 electrons from 4s
Ni²⁺ = [Ar] 3d⁸
d⁸ → 2 unpaired electrons
Matches (IV)
(D) Fe²⁺
Fe = [Ar] 3d⁶ 4s²
Fe²⁺ → remove 2 electrons from 4s
Fe²⁺ = [Ar] 3d⁶
d⁶ → 4 unpaired electrons
Matches (II)
(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
Correct option is 3