Match List-I with List-II.

Choose the correct answer from the options given below:

(A) - (I), (B) - (III), (C) - (IV), (D) - (II)

The correct answer is Option (3) → (A) - (I), (B) - (III), (C) - (IV), (D) - (II)

Match List-I with List-II.

 Number of unpaired electrons depends on electronic configuration of ions.

(A) Zn²⁺

Zn = [Ar] 3d¹⁰ 4s²

Zn²⁺ → remove 2 electrons from 4s

Zn²⁺ = [Ar] 3d¹⁰

All electrons paired → 0 unpaired

Matches (I)

(B) Cu²⁺

Cu = [Ar] 3d¹⁰ 4s¹

Cu²⁺ → remove 1 from 4s and 1 from 3d

Cu²⁺ = [Ar] 3d⁹

d⁹ → 1 unpaired electron

Matches (III)

(C) Ni²⁺

Ni = [Ar] 3d⁸ 4s²

Ni²⁺ → remove 2 electrons from 4s

Ni²⁺ = [Ar] 3d⁸

d⁸ → 2 unpaired electrons

Matches (IV)

(D) Fe²⁺

Fe = [Ar] 3d⁶ 4s²

Fe²⁺ → remove 2 electrons from 4s

Fe²⁺ = [Ar] 3d⁶

d⁶ → 4 unpaired electrons

Matches (II)

(A)-(I), (B)-(III), (C)-(IV), (D)-(II)

Correct option is 3