Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Communication

Question:

In an interference pattern, the ratio of intensity of two waves is \(\frac{9}{25}\), then the ratio of maximum intensity to minimum intensity is: 

Options:

16 : 1 

1 : 9

3 : 5

5 : 3

Correct Answer:

16 : 1 

Explanation:

$\frac{I_{max}}{I_{min}} =(\frac{ \sqrt{\frac{I_1}{I_2} + 1}}{ \sqrt{\frac{I_1}{I_2} - 1}})^2 =( \frac{ \sqrt{\frac{25}{9} + 1}}{ \sqrt{\frac{25}{9} - 1}})^2 = 16:1$