Study the given figure and answer the question that follows.

Find the length of AB in the given triangle, if it is given that the length of BD is 4 unit.

4

In the given triangle

\(\Delta \)ABC is similar to \(\Delta \)ADE

Then according to the theorem

Sides, \(\frac{AD}{AB}\) = \(\frac{DE}{BC}\)

= Let the length of AB x units.

= \(\frac{AB\;+\;BD}{AB}\) = \(\frac{DE}{BC}\)

= \(\frac{x\; + \;4}{x}\) = \(\frac{6}{3}\)

= 3x + 12 = 6x

= 12 = 3x

= x = 4

Therefore, the length of AB is 4 units.