Practicing Success
A radio antenna of height 150 m stands on top of a building. At a point on the ground, the angle of elevation of bottom of antenna is 45° and the top of antenna is 60°. What is the height of the building? |
75(3 - √3) m 75(√3 + 1) m 300 m 75 m |
75(√3 + 1) m |
tan 45° = 1 : 1 (BC) (CD) = x tan 60° = \(\sqrt {3}\) : 1 (AC) (CD) ↓ ↓ \(\sqrt {3}\)x = x AB = AC - BC 150 = \(\sqrt {3}\)x - x ⇒ x = \(\frac{150}{\sqrt {3} - 1}\) ⇒ x = 75 (\(\sqrt {3}\) + 1) m
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