The following table shows the number of tables and the number of chairs made of 5 different metals sold by a furniture store over a given time period.
|
Metal |
Tables |
Chairs |
|
M1 |
100 |
50 |
|
M2 |
150 |
70 |
|
M3 |
120 |
40 |
|
M4 |
125 |
25 |
|
M5 |
200 |
60 |
N = Average number of chairs sold per metal
The number of tables sold that were made of metal M3 is approximately what percentage more than N?
Answer & explanation
Correct answer: option 1
Average number of chairs sold = \(\frac{50 + 70 + 40 + 25 + 60}{5}\)
= \(\frac{245 }{5}\)
= 49
Number of tables sold of M3 = 120
Required percentage = \(\frac{120 - 49 }{49}\) × 100
= \(\frac{71 }{49}\) × 100
= 144.90%