The following table shows the number of tables and the number of chairs made of 5 different metals sold by a furniture store over a given time period.

N = Average number of chairs sold per metal

The number of tables sold that were made of metal M3 is approximately what percentage more than N?

144.90%

Average number of chairs sold = \(\frac{50 + 70 + 40 + 25 + 60}{5}\)

= \(\frac{245 }{5}\)

= 49

Number of tables sold of M3 = 120

Required percentage = \(\frac{120 - 49 }{49}\) × 100

= \(\frac{71 }{49}\) × 100

= 144.90%