Practicing Success
Function $f(x)=\cos \left(\log \left(x+\sqrt{1+x^2}\right)\right)$ is : |
even odd neither even nor odd None of these |
even |
$f(-x)=\cos \left(\log \left(-x+\sqrt{1+x^2}\right)\right)$ $=\cos \left(\log \frac{\left(\sqrt{1+x^2}-x\right)\left(\sqrt{1+x^2}+x\right)}{\sqrt{1+x^2}+x}\right)$ $=\cos \left(\log \left(\frac{1}{\sqrt{1+x^2}+x}\right)\right)$ $=\cos \left(-\log \sqrt{1+x^2}+x\right)$ $=\cos \left(\log \left(\sqrt{1+x^2}+x\right)\right)=f(x)$ Hence f(x) is even Hence (1) is the correct answer. |