If the numerator of a fraction is increased by 60% and the denominator is increased by 40%, then the resultant fraction is $\frac{16}{63}$.The original fraction is :

$\frac{2}{9}$

Let original fraction = \(\frac{x}{y}\)

the numerator of a fraction is increased by 60% and the denominator is increased by 40%

 \(\frac{160x}{140y}\)  = \(\frac{16}{63}\)

On solving ,

\(\frac{x}{y}\) = \(\frac{2}{9}\)