$\int\frac{dx}{x^a}=$1$\frac{x^{1-a}}{1-a}+C$ for all $a∈R$2$2\sqrt{x+1}+C$ for $a=\frac{1}{2}$3$\frac{3}{2}x^{\frac{3}{2}}+C$ for $a=\frac{-1}{2}$4$\frac{3}{4}x^{\frac{3}{4}}+C$ for $a=\frac{-1}{3}$Answer & explanation+Correct answer: option 1$\int x^{-a}dx=\frac{x^{1-a}}{1-a}+C$
