Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Percentages

Question:

The numerator of a fraction is increased by 20% and denominator is decreased by 20%. The value of the fraction becomes \(\frac{4}{5}\).  The original fraction is:

Options:

\(\frac{2}{3}\)

\(\frac{8}{15}\)

\(\frac{7}{11}\)

\(\frac{4}{5}\)

Correct Answer:

\(\frac{8}{15}\)

Explanation:

Let the fraction is  =\(\frac{x}{y}\)

ATQ,

⇒ 120% of x : 80% of y = 4 : 5

⇒ \(\frac{120x}{80y}\) = \(\frac{4}{5}\)

⇒ \(\frac{3x}{2y}\) = \(\frac{4}{5}\)

⇒ \(\frac{x}{y}\) = \(\frac{8}{15}\)