Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Mixture and Alligation

Question:

The number of students in section C and section D of a class are 50 and 62 respectively. The average score in English of all the students is 75. If the average score of student in section C is 20% more than that of student in section D, then what is the average score of students in section C ?

Options:

82.7

82.8

82.6

83.6

Correct Answer:

82.6

Explanation:

                  Section                      Section

                      C                               D

                     50                              62

Total score as per question,

                    50 + 60 = 112 × 75 = 8400 -------- (i)

The average score of section C is = \(\frac{6x}{5}\)  ---- (ii)

The average score of section D is = x  --------  (iii)

Section C = 50 × \(\frac{6x}{5}\) = 60 x

Section D = 62 × x = 62 x

60 x + 62 x = 8400 (From above (i) equation)

122 x = 8400

x = \(\frac{8400}{122}\) = 68.85 (Put this value in equation (ii))

Section C = \(\frac{6 × 68.85}{5}\) = 82.62