In a certain town 25% families own a phone and 15% own a car, 65% families own neither a phone nor a car. 2000 families own both a car and a phone.

Consider the following statements in this regard:

1. 10% families own both a car and a phone

2. 35% families own either a car or a phone

3. 40,000 families live in the town

Which of the following statements are correct?

2 and 3

Let there be x families in the town. Let P and C denote the set of families using phone and car respectively.

Then,

$n(P)=\frac{25x}{100}=\frac{x}{4},n(C)=\frac{15x}{100}=\frac{3x}{20}$

and, $n(\bar{P}∩\bar{C})=\frac{65x}{100}=\frac{13x}{20}$

Also, $n(P∩C)=2000$

Now,

$n(\bar{P}∩\bar{C})=\frac{13x}{20}$

$⇒n(\overline{P∩C})=\frac{13x}{20}$

$⇒n(U)-n(P∪C)=\frac{13x}{20}$

$⇒x-\{n(P)+n(C)-n(P∩C)\}=\frac{13x}{20}$

$⇒x-(\frac{x}{4}+\frac{3x}{20}-2000)=\frac{13x}{20}⇒\frac{x}{20}=2000⇒x=40000$

Thus, statement 3 is true.

10% of the total families in the town is 4000 and it is given that 2000 families own both a car and a phone. So, statement 1 is not true.

Now,

$n(P∪C)=n (P) + n (C) -n (P∩C)$

$⇒n (P∩C)=\frac{x}{4}+\frac{3x}{20}-2000$

$⇒n (P∩C)=10000+6000-2000=14000$

$⇒n (P∩C)$ = 35% of 40000

Thus, statement 3 is correct.