Practicing Success
Practicing Success
CUET Preparation Today
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a b c d |
b |
$ K.E (K) = E - \phi = \frac{hc}{\lambda} - \phi $ $ K_1 = \frac{hc}{\lambda} - \phi $ $ K_2 = \frac{2hc}{\lambda} - \phi $ $ K_2 = 3 K_1 $ $\Rightarrow \frac{2hc}{\lambda} - \phi = 3\frac{hc}{\lambda} - 3\phi $ $ \Rightarrow 2\phi = \frac{hc}{\lambda}$ $ \Rightarrow \phi = \frac{hc}{2\lambda}$
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