A, B and C can separately do a work in 6, 10 and 15 days respectively. They started to work together but C left after 2 days. In how many days will the remaining work be finished?

$1\frac{1}{4}$

A = 6D, B = 10D, C= 15D

⇒Here, all of them worked together for 2 days, therefore,

⇒ Work done by all of them in 2 days = (5+3+2) x 2 = 20    (Efficiency × Days = Total work)

⇒ now, C left and remaining work is done by A & B.

⇒ Remaining work = 30 - 20 = 10

Therefore, The Time taken by A & B to complete the remaining work = \(\frac{10}{8}\) = \( {1 }_{4 }^{1 } \) Days.