Practicing Success
Practicing Success
CUET Preparation Today
f: R → R given by $f (x) = x + \sqrt{x^2}$, is |
injective surjective bijective none of these |
none of these |
The correct answer is Option (4) → none of these We have, $f(x) = x + \sqrt{x^2} = x+|x|=\left\{\begin{matrix}2x,&x≥0\\x-x=0,&x<0\end{matrix}\right.$ Clearly, f is many-one into function. |
