If $\mu $ is mean of random variable X,

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Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Probability Distributions

Question:

If $\mu $ is mean of random variable X, with probability distribution

x	0	1	2
P(X=x)	$\frac{4}{9}$	$\frac{4}{9}$	$\frac{1}{9}$

then value of $9 \mu + 4 $ is :

Options:

Correct Answer:

Explanation:

The correct answer is Option (3) → 10

The mean $μ=E(X)$ is,

$E(X)=∑xP(X=x)$

$=0×\frac{4}{9}+1×\frac{4}{9}+2×\frac{1}{9}$

$=\frac{2}{3}$

$9μ+4=9×(\frac{2}{3})+4$

$=6+4=10$