If $\mu $ is mean of random variable X, with probability distribution
| x | 0 | 1 | 2 |
| P(X=x) | $\frac{4}{9}$ | $\frac{4}{9}$ | $\frac{1}{9}$ |
then value of $9 \mu + 4 $ is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 10
The mean $μ=E(X)$ is,
$E(X)=∑xP(X=x)$
$=0×\frac{4}{9}+1×\frac{4}{9}+2×\frac{1}{9}$
$=\frac{2}{3}$
$9μ+4=9×(\frac{2}{3})+4$
$=6+4=10$