For an RLC circuit driven with voltage of amplitude $v_m$ and frequency $ω_0=\frac{1}{\sqrt{LC}}$ the current exhibits resonance. The quality factor, Q is given by:
Answer & explanation
Correct answer: option 3
Quality factor $Q = \frac{1}{R} \sqrt{\frac{L}{C}}$
$\omega^2 = \frac{1}{LC}$
$\Rightarrow C = \frac{1}{\omega^2L}$
$\Rightarrow Q= \frac{\omega L}{R}$