Suman travels from place X to Y and Rekha travels from Y to X, simultaneously. After meeting on the way, Suman and Rekha reach Y and X, in 3 hours 12 minutes and one hour 48 minutes, respectively. If the speed of Rekha is 9 km/h, then the speed (in km/h) of Suman is:

$6 \frac{3}{4}$

\(\frac{S1}{S2}\)2 = \(\frac{T2}{T1}\)


Let the speed of Suman be S1

According to the question

\(\frac{S}{9}\)2 = \(\frac{9 × 5}{16 ×5  }\)

\(\frac{S}{9}\)2 = \(\frac{9 }{16   }\)

\(\frac{S}{9}\) = \(\frac{3 }{4   }\)

4S = (9 × 3)

4S = 27

S = \(\frac{27}{4}\)

S =  6\(\frac{3}{4}\) km/h

So , The speed of Suman is = 6\(\frac{3}{4}\) km/h