Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:
$x=a(\cos \theta+\theta\sin \theta), y=a(\sin \theta-\theta\cos\theta).$ What is $\frac{dy}{dx}$?
Options:
$\tan \theta$
$\sin \theta$
$\sec \theta$
$\cot \theta$
Correct Answer:
$\tan \theta$
Explanation:
$\frac{dx}{d\theta}=a\theta\cos\theta$, $\frac{dy}{d\theta}=a\theta\sin \theta$. Hence $\frac{dy}{dx}=\frac{dy}{d\theta}/\frac{dx}{d\theta}=\tan \theta$