The correct order of reactivity of 1º, 2º and 3º alcohols towards sodium metal is 

1º >2º > 3º

The correct answer is option 1. 1º >2º > 3º.

The reactivity of alcohols towards sodium metal is primarily influenced by the steric hindrance around the hydroxyl group (-OH) and the electron-donating effects of alkyl groups attached to the carbon bearing the -OH group. Sodium reacts with alcohols to form alkoxides and hydrogen gas. The reactivity decreases as the steric hindrance around the -OH group increases.

Let us analyze each type of alcohol:

1. 1º Alcohols (Primary alcohols): The carbon bearing the -OH group is attached to only one other carbon atom (or no other carbons in the case of methanol). This leads to minimal steric hindrance and higher reactivity towards sodium.

2. 2º Alcohols (Secondary alcohols): The carbon bearing the -OH group is attached to two other carbon atoms. This increases the steric hindrance compared to primary alcohols, resulting in lower reactivity

3. 3º Alcohols (Tertiary alcohols): The carbon bearing the -OH group is attached to three other carbon atoms. This creates significant steric hindrance, making it the least reactive towards sodium.

Given this, the correct order of reactivity towards sodium metal is: 1º > 2º > 3º

So, the correct answer is: 1º > 2º > 3º