Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

What would be the maximum height reached by the body if the body is projected vertically from the surface of the earth of radius R with a velocity equal to half of the escape velocity?

Options:

2R

R

R/2

R/3

Correct Answer:

R/3

Explanation:

Conservation of Energy : \(E_i= E_f\)

... where E : total energy ; Ei = total energy initial ; Ef = total energy final

\(\Rightarrow T_i + U_i = T_f + U_f\)

... where T : kinetic energy ; Ti = kinetic energy initial ; Tf = kinetic energy final, and 

... where U : potential energy ; Ui = potential energy initial ; Uf = potential energy final

\(\frac{1}{2}m \frac{v^2_e}{4} + [-\frac{GMm}{R}] = -\frac{GMm}{R+H}\)

\(\frac{2GMm}{8R} - \frac{GMm}{R} = -\frac{GMm}{R+H}\) ... (\(because v^2_e = \frac{2GM}{R}\))

\(-\frac{3GMm}{4R} = -\frac{GMm}{R+H}\)

\(R+H = \frac{4}{3}R\)

\(\Rightarrow H = \frac{R}{3}\)