If in the given figure, ∠ACB + ∠BAC = 70°, ∠BDE = 45° and ∠BCE = 25°; then the marked angle ∠CED is?

95° 115° 45° 140°

140°

∠CED = ? ∠CBD = ∠CAB + ∠ACB = 70° (exterior angle) ∠BCE = 25° ∠CTD = 70° + 25° = 95° ∠CED = ∠ETD + ∠EDT = 95° + 45° = 140°