If \(3A=5B=9C\), then \(A:B:C\) is equal to:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 15 : 9 : 5
When \(3A\), \(5B\) and \(9C\) are equal, set each of them equal to a common multiple of 3, 5 and 9. The smallest one is 45.
\(3A=5B=9C=45t\)
\(\displaystyle A=\frac{45t}{3}=15t\)
\(\displaystyle B=\frac{45t}{5}=9t\)
\(\displaystyle C=\frac{45t}{9}=5t\)
So \(A:B:C=\) 15 : 9 : 5.