The combination of the same two inductors (33 mH and 55 mH) connected in parallel without mutual inductance will have what value?
Answer & explanation
Correct answer: option 4
The correct answer is Option 4: 21 mH
For inductors connected in parallel (without mutual inductance) :
$\frac{1}{L_{eq}} = \frac{1}{L_1} + \frac{1}{L_2}$ or $L_{eq} = \frac{L_1 \times L_2}{L_1 + L_2}$
Given:
-
$L_1 = 33\text{ mH}$
-
$L_2 = 55\text{ mH}$
$L_{eq} = \frac{33 \times 55}{33 + 55}$
$L_{eq} = \frac{1815}{88}$
$L_{eq} \approx 20.625\text{ mH}$
Rounding to the nearest whole number gives 21 mH.