CUET Preparation Today
The combination of the same two inductors (33 mH and 55 mH) connected in parallel without mutual inductance will have what value? |
88 mH 22 mH 1.8 H 21 mH |
21 mH |
The correct answer is Option 4: 21 mH For inductors connected in parallel (without mutual inductance) : $\frac{1}{L_{eq}} = \frac{1}{L_1} + \frac{1}{L_2}$ or $L_{eq} = \frac{L_1 \times L_2}{L_1 + L_2}$
Given:
$L_{eq} = \frac{33 \times 55}{33 + 55}$
$L_{eq} = \frac{1815}{88}$
$L_{eq} \approx 20.625\text{ mH}$
Rounding to the nearest whole number gives 21 mH.
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