Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

Which of the following is the solution of the given differential equation?

y'=1+\( { y}^{ 2} \)/1+ \( { x}^{ 2} \)

Options:

A\(\tan^{-1} {y}\) = \(\tan^{-1} {x}\) + B

\(\tan^{-1} {y}\) = \(\tan^{-1} {x}\) + A

A\(\tan^{-1} {y}\) = C\(\tan^{-1} {x}\) + B

A\(\tan^{-1} {y}\) = C\(\tan^{-1} {x}\)

Correct Answer:

\(\tan^{-1} {y}\) = \(\tan^{-1} {x}\) + A

Explanation:

Number of arbitrary constants is equal to the order of the equation.