In a ΔXYZ, XO is the median and $XO - \frac{1}{2}YZ$. If ∠YXO = 30°, then what is the value of ∠XYZ?
Answer & explanation
Correct answer: option 3
According to the question,
in triangle XOY,
As XO is median, So
⇒ YO = OZ
⇒ and as XO = \(\frac{1}{2}\) YZ, then
⇒ XO = YO + OZ
In triangle XYO,
⇒ XO = OY
So the triangle XYO is an isosceles triangle
⇒ So, \(\angle\)YXO = \(\angle\)XYO = \({30}^\circ\)
⇒ and \(\angle\)XYO = \(\angle\)XYZ
⇒ \(\angle\)XYZ = \({30}^\circ\)
Therefore, the required value is \({30}^\circ\)