If $\left(2 \mathrm{a}+\frac{3}{a}-1\right)=11$, what is the value of $\left(4 a^2+\frac{9}{a^2}\right) ?$
Answer & explanation
Correct answer: option 3
If $K+\frac{1}{K}=n$
then, $K^2+\frac{1}{K^2}$ = n2 – 2
If $\left(2 \mathrm{a}+\frac{3}{a}-1\right)=11$
Then, $\left(2 \mathrm{a}+\frac{3}{a}\right)=11+1=12$
what is the value of $\left(4 a^2+\frac{9}{a^2}\right) ?$ = 122 – 2 × 2 × 3 = 132