Practicing Success
A block A of mass m1 rests on a horizontal table. A light string connected to it passes over a frictionless pulley at the edge of table and from its other end another block B of mass m2 is suspended. The coefficient of kinetic friction between the block and the table is µk . When the block A is sliding on the table, the tension in the string is :- |
\(\frac{(m_2 - \mu_k m_1)g}{m_1 + m_2}\) \(\frac{m_1m_2(1 + \mu_k )g}{m_1 + m_2}\) \(\frac{m_1m_2(1 - \mu_k )g}{m_1 + m_2}\) \(\frac{(m_2 + \mu_k m_1)g}{m_1 + m_2}\) |
\(\frac{m_1m_2(1 + \mu_k )g}{m_1 + m_2}\) |
For the motion of both blocks : \(m_2 g - T = m_2 a\) \(T - \mu_k m_1g = m_1 a\) ⇒ a = \(\frac{(m_2 - \mu_k m_1)g}{m_1 + m_2}\) For the motion of block of mass m2 \(m_2 g - T = m_2 [\frac{m_2 - \mu_k m_1}{m_1 + m_2}]g ⇒ T = \(\frac{m_1m_2(1 + \mu_k )g}{m_1 + m_2}\)
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