Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Laws of Motion

Question:

A block A of mass m1 rests on a horizontal table. A light string connected to it passes over a frictionless pulley at the edge of table and from its other end another block B of mass m2 is suspended. The coefficient of kinetic friction between the block and the table is µk . When the block A is sliding on the table, the tension in the string is :-

Options:

\(\frac{(m_2 - \mu_k m_1)g}{m_1 + m_2}\)

\(\frac{m_1m_2(1 + \mu_k )g}{m_1 + m_2}\)

\(\frac{m_1m_2(1 - \mu_k )g}{m_1 + m_2}\)

\(\frac{(m_2 + \mu_k m_1)g}{m_1 + m_2}\)

Correct Answer:

\(\frac{m_1m_2(1 + \mu_k )g}{m_1 + m_2}\)

Explanation:

For the motion of both blocks : 

\(m_2 g - T = m_2 a\)

\(T - \mu_k m_1g = m_1 a\)

⇒ a = \(\frac{(m_2 - \mu_k m_1)g}{m_1 + m_2}\)

For the motion of block of mass m2

\(m_2 g - T = m_2 [\frac{m_2 - \mu_k m_1}{m_1 + m_2}]g

⇒ T = \(\frac{m_1m_2(1 + \mu_k )g}{m_1 + m_2}\)