A block A of mass m1 rests on a horizontal table. A light string connected to it passes over a frictionless pulley at the edge of table and from its other end another block B of mass m2 is suspended. The coefficient of kinetic friction between the block and the table is µk . When the block A is sliding on the table, the tension in the string is :-
Answer & explanation
Correct answer: option 2
For the motion of both blocks :
\(m_2 g - T = m_2 a\)
\(T - \mu_k m_1g = m_1 a\)
⇒ a = \(\frac{(m_2 - \mu_k m_1)g}{m_1 + m_2}\)
For the motion of block of mass m2
\(m_2 g - T = m_2 [\frac{m_2 - \mu_k m_1}{m_1 + m_2}]g
⇒ T = \(\frac{m_1m_2(1 + \mu_k )g}{m_1 + m_2}\)