If A and B are two events such that $P(A) ≠ 0$ and $P(B | A) = 1$ then |
$A⊂B$ $B⊂A$ $B=\phi$ $A=\phi$ |
$A⊂B$ |
The correct answer is Option (1) → $A⊂B$ Given: $P(B|A) = 1$ and $P(A) \ne 0$ From conditional probability: $P(B|A) = \frac{P(A \cap B)}{P(A)} = 1$ So, $P(A \cap B) = P(A)$ This implies that all outcomes of $A$ are contained in $B$. Therefore, $A \subseteq B$ |