The average kinetic energy of the thermal neutrons is of the order of (Boltzmann's constant $K_B=8 \times 10^{-5}$ eV/Kelvin)
Answer & explanation
Correct answer: option 1
$ E = kT = 8 \times 10^{-5} \times 300 = 0.03eV$
The average kinetic energy of the thermal neutrons is of the order of (Boltzmann's constant $K_B=8 \times 10^{-5}$ eV/Kelvin)
Correct answer: option 1
$ E = kT = 8 \times 10^{-5} \times 300 = 0.03eV$