CUET Preparation Today
A square loop of copper wire is pulled through a region of uniform magnetic field as shown. Rank the pulling forces $F_A,F_B, F_C$ and $F_D$ that must be applied to keep the loop moving with constant speed $(\vec v)$:
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$F_B=F_D. F_A=F_C$ $F_C<F_B<-F_D>F_A$ $F_C>F_D>F_B>F_A$ $F_D>F_B>F_A=F_C$ |
$F_B=F_D. F_A=F_C$ |
The correct answer is Option (1) → $F_B=F_D. F_A=F_C$ |
