For A = 30°, find the value of : $\frac{-3sin^22A+2sec^2A -tan\frac{3A}{2}}{\frac{1}{3}sin3A}$

$-\frac{7}{4}$

$\frac{-3sin^22A+2sec^2A -tan\frac{3A}{2}}{\frac{1}{3}sin3A}$

= $\frac{-3sin^260º+2sec^230º -tan\frac{90º}{2}}{\frac{1}{3}sin90º}$

= \(\frac{- 3× 3/4 + 2×(2/√3)² - 1  }{ 1/3}\)

= \(\frac{- 9/4 + 8/3 - 1  }{ 1/3}\)

= \(\frac{(-27+32-12)/12  }{ 1/3}\)

= \(\frac{-7/12  }{ 1/3}\)

= \(\frac{-7  }{ 4}\)

−3sin22A+2sec2A−tan3A213sin3A

−3sin22A+2sec2A−tan3A213sin3A