What is the length (in cm) of the longest rod that can be fitted in a box of dimensions 28 cm × 4 cm × 10 cm ?

42 36 30 25

30

We know that, Diagonal of cuboid = \(\sqrt {(l^2 + b^2  + h^2 ) }\) Given, Dimensions of box = 28 × 4 × 10 Diagonal of given cuboid box = \(\sqrt {(28^2 + 4^2  + 10^2 ) }\)= \(\sqrt {(784 + 16  + 100 ) }\) = \(\sqrt {(900}\)) = 30cm