When the distance between the object and the screen is more than 4f, we can obtain the image of the object on the screen for the two positions of a convex lens of focal length f. It is called displacement method. In one case the image is magnified. If $I_1$ and $I_2$ be the sizes of the two images, then the size of the object is:
Answer & explanation
Correct answer: option 4
If $I_1 = mI_0$ where m is magnification and $I_0$ is actual size
$I_2 = I_0/m$
$∴ I_0 = \sqrt{I_1 I_2}$