Practicing Success
When the distance between the object and the screen is more than 4f, we can obtain the image of the object on the screen for the two positions of a convex lens of focal length f. It is called displacement method. In one case the image is magnified. If $I_1$ and $I_2$ be the sizes of the two images, then the size of the object is: |
$(I_1 + I_2)/2$ $I_1 − I_2$ $\sqrt{(I_1 I_2)}$ $\sqrt{(I_1/I_2)}$ |
$\sqrt{(I_1/I_2)}$ |
If $I_1 = mI_0$ where m is magnification and $I_0$ is actual size $I_2 = I_0/m$ $∴ I_0 = \sqrt{I_1 I_2}$ |