If cosec θ $=\frac{41}{9}$ and θ is an acute angle, then the value of 5 tan θ will be:
Answer & explanation
Correct answer: option 4
cosec θ = \(\frac{41 }{9}\) = \(\frac{H }{P}\)
B y using pythogoras theorem ,
H² = B² + P²
(41)² = B² + (9)²
B² = 1681 - 81 = 1600
B = 40
Now ,
5 tan θ = 5 × \(\frac{9 }{40}\) ( tan θ = \(\frac{P }{B}\) )
= \(\frac{9 }{8}\)