Practicing Success
The vector equation of the line joining the points $(-2,-3,-4)$ and $(1,-2,4)$ is : |
$\vec{r}=(-2 \hat{i}-3 \hat{j}-4 \hat{k})+\lambda(\hat{i}-2 \hat{j}+4 \hat{k})$ $\vec{r}=(2 \hat{i}+3 \hat{j}+4 \hat{k})+\lambda(3 \hat{i}-\hat{j}+8 \hat{k})$ $\vec{r}=(-2 \hat{i}-3 \hat{j}-4 \hat{k})+\lambda(3 \hat{i}+\hat{j}+8 \hat{k})$ $\vec{r}=(2 \hat{i}+3 \hat{j}+4 \hat{k})+\lambda(3 \hat{i}+\hat{j}+8 \hat{k})$ |
$\vec{r}=(-2 \hat{i}-3 \hat{j}-4 \hat{k})+\lambda(3 \hat{i}+\hat{j}+8 \hat{k})$ |
$\vec{x}_1=-2 \hat{i}-3 \hat{j}-4 \hat{k}$ $\vec{x}_2=1 \hat{i}-2 \hat{j}+4 \hat{k}$ so vector parallel to given line is $\left(\vec{x}_2-\vec{x}_1\right)= 3 \hat{i}+\hat{j}+8 \hat{k}$ So equation of lines is $\vec{r}=\vec{a}+\lambda \vec{b}$ → vector parallel to line |