The vector equation of the line joining the points (-2,-3,-4) and (1,…

$\vec{x}_1=-2 \hat{i}-3 \hat{j}-4 \hat{k}$

$\vec{x}_2=1 \hat{i}-2 \hat{j}+4 \hat{k}$

so vector parallel to given line is $\left(\vec{x}_2-\vec{x}_1\right)= 3 \hat{i}+\hat{j}+8 \hat{k}$

So equation of lines is

$\vec{r}=\vec{a}+\lambda \vec{b}$ → vector parallel to line

$\vec{r}=(-2 \hat{i}-3 \hat{j}-4 \hat{k})+\lambda(3 \hat{i}+\hat{j}+8 \hat{k})$