If the mean of a binomial distribution is 5 and its standard deviation is 1, then the probability of ten successes is :

${^{25}C}_{10}\left(\frac{1}{5}\right)^{10}\left(\frac{4}{5}\right)^{15}$ ${^{15}C}_{10}\left(\frac{4}{5}\right)^{10}\left(\frac{1}{5}\right)^{15}$ ${^{25}C}_{10}\left(\frac{1}{5}\right)^{15}\left(\frac{4}{5}\right)^{10}$ ${^{20}C}_{10}\left(\frac{1}{5}\right)^{10}\left(\frac{4}{5}\right)^{10}$

${^{25}C}_{10}\left(\frac{1}{5}\right)^{10}\left(\frac{4}{5}\right)^{15}$