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If the mean of a binomial distribution is 5 and its standard deviation is 1, then the probability of ten successes is : |
${^{25}C}_{10}\left(\frac{1}{5}\right)^{10}\left(\frac{4}{5}\right)^{15}$ ${^{15}C}_{10}\left(\frac{4}{5}\right)^{10}\left(\frac{1}{5}\right)^{15}$ ${^{25}C}_{10}\left(\frac{1}{5}\right)^{15}\left(\frac{4}{5}\right)^{10}$ ${^{20}C}_{10}\left(\frac{1}{5}\right)^{10}\left(\frac{4}{5}\right)^{10}$ |
${^{25}C}_{10}\left(\frac{1}{5}\right)^{10}\left(\frac{4}{5}\right)^{15}$ |
The correct answer is Option (1) → ${^{25}C}_{10}\left(\frac{1}{5}\right)^{10}\left(\frac{4}{5}\right)^{15}$ 'n' here is not a whole numbers, verified after calculation. Hence, this can't be solved. |
