Practicing Success
Four equal charges Q are placed at the four corners of a square of side 'a'. Work done in removing a charge -Q from its centre to infinity is: |
zero $\frac{\sqrt{2} Q^2}{4 \pi \epsilon_{o} a} V$ $\frac{\sqrt{2} Q^2}{\pi \epsilon_{o} a} V$ $\frac{-Q^2 \sqrt{2}}{2 \pi \epsilon_{o} a} V$ |
$\frac{\sqrt{2} Q^2}{\pi \epsilon_{o} a} V$ |
The correct answer is Option (3) → $\frac{\sqrt{2} Q^2}{\pi \epsilon_{o} a} V$ |